You may want to review solving quadratic equations first.

Remember systems of equations? Now, you can solve systems where
one equation is quadratic. For example, the two equations could be
−2*y*^{2} + 4 = 2*x**y*
+ *y*^{2} + 3*x* − 2*y* + 4 and
−*y* − 1 = *x* + 1. To solve these, you use
substitution. What this means in this case is that you first
solve the linear equation for *y*, getting *y* =
−*x* − 2. Then, you plug that into the other
equation wherever you see *y*. This simplifies to
−*x*^{2} + 13*x* + 16 = 0, whose solutions
are −13 ⁄ 2 + 1 ⁄ 2
* √105 and −13 ⁄ 2 −
1 ⁄ 2 * √105. You can then plug these in
to get *y*, so the two solutions are
(−13 ⁄ 2 + 1 ⁄ 2 *
√105, 9 ⁄ 2 −
1 ⁄ 2 * √105) and
(−13 ⁄ 2 −
1 ⁄ 2 * √105, 9 ⁄ 2
+ 1 ⁄ 2 * √105).