You may want to review solving quadratic equations first.

Remember systems of equations? Now, you can solve systems where one equation is quadratic. For example, the two equations could be −2y2 + 4 = 2xy + y2 + 3x − 2y + 4 and −y − 1 = x + 1. To solve these, you use substitution. What this means in this case is that you first solve the linear equation for y, getting y = −x − 2. Then, you plug that into the other equation wherever you see y. This simplifies to −x2 + 13x + 16 = 0, whose solutions are −13 ⁄ 2 + 1 ⁄ 2 * √105 and −13 ⁄ 2 − 1 ⁄ 2 * √105. You can then plug these in to get y, so the two solutions are (−13 ⁄ 2 + 1 ⁄ 2 * √105, 9 ⁄ 2 − 1 ⁄ 2 * √105) and (−13 ⁄ 2 − 1 ⁄ 2 * √105, 9 ⁄ 2 + 1 ⁄ 2 * √105).