You may want to review multiplying terms with roots and quadratic equations first.
To solve equations involving radicals, you want to get the term with the radical in it by itself on one side. For example, if you have to solve 3√(x − 1) − 1 = −x, you add 1 to both sides to get 3√(x − 1) = −x + 1. Next, you square both sides. The square of the left-hand side is 9(x − 1) (remember the definition of square roots), and the square of the right-hand side is x2 − 2x + 1, so the new equation is 9(x − 1) = x2 − 2x + 1. This is just a quadratic equation that we need to solve. (Sometimes we're lucky and it's linear instead.) Getting everything on one side gives us x2 − 11x + 10 = 0. This has two solutions: x = 1 or x = 10.
We're not quite done. The problem is that squaring both sides of an equation can add solutions that weren't there before. So it's essential that you check these solutions in the original equation. (Of course, checking is a good idea even with simpler equations; but here it's necessary.) When we do that, we find that x = 1 checks out (both sides come out to −1) but x = 10 doesn't (the left-hand side comes out to 8, the right-hand side to −10). So x = 1 is the only solution.